Matematyka
$f\left(x\right) =$ |
$\arccos\left({x}^{2}\right)+\sin\left(3\right){\cdot}x$
Note: Your input has been rewritten/simplified. |
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$\dfrac{\mathrm{d}\left(f\left(x\right)\right)}{\mathrm{d}x} =$ |
$\class{steps-node}{\cssId{steps-node-1}{\tfrac{\mathrm{d}}{\mathrm{d}x}\kern-.25em\left(\arccos\left({x}^{2}\right)+\sin\left(3\right){\cdot}x\right)}}$ $=\class{steps-node}{\cssId{steps-node-2}{\class{steps-node}{\cssId{steps-node-3}{\tfrac{\mathrm{d}}{\mathrm{d}x}\kern-.25em\left(\arccos\left({x}^{2}\right)\right)}}+\sin\left(3\right)}}$ $=\class{steps-node}{\cssId{steps-node-4}{\dfrac{-1}{\sqrt{1-{\left({x}^{2}\right)}^{2}}}}}{\cdot}\class{steps-node}{\cssId{steps-node-5}{\tfrac{\mathrm{d}}{\mathrm{d}x}\kern-.25em\left({x}^{2}\right)}}+\sin\left(3\right)$ $=\sin\left(3\right)-\dfrac{\class{steps-node}{\cssId{steps-node-6}{2}}\class{steps-node}{\cssId{steps-node-7}{x}}}{\sqrt{1-{x}^{4}}}$ |